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x^2+3.5=3.75
We move all terms to the left:
x^2+3.5-(3.75)=0
We add all the numbers together, and all the variables
x^2-0.25=0
a = 1; b = 0; c = -0.25;
Δ = b2-4ac
Δ = 02-4·1·(-0.25)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1}{2*1}=\frac{-1}{2} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1}{2*1}=\frac{1}{2} =1/2 $
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